Situations where streaming statistics are useful:
- Unknown number of observations
- Online streaming data
- Dataset too big for local processing
For the remainder, let’s consider a set of observations , weights , such that
0
- Mean and variances
A naive approach to calculating a weighted streaming mean, and unbiased streaming variance, , would be to calculate:
1
where
2
This calculation however does not hold for large values.
An alternative calculation was suggested by West1 cite:&west1979updating West, D. (1979). Updating mean and variance estimates: an improved method. Communications of the ACM, 22(9), 532–535. , where we calculate:
3
Let’s look at an example in Python.
from plotutils import *
import numpy as np
mu = 10.0
sigma = 20.0
N = 100_000
Y = np.random.normal(loc=mu, scale=sigma, size=N)
import matplotlib.pyplot as plt
import matplotlib
matplotlib.rc('figure', figsize=(12, 6))
plt.hist(Y, bins=50,color="lightpink")
plt.show()

As expected, the mean and variance when calculated in “batch” mode should be equivalent to the original values and .
print(f"mean: {np.mean(Y)}")
print(f"std: {np.std(Y)}")
mean: 10.040100563607174
std: 19.946298541957912
class StreamingStatistcs:
def __init__(self):
self.sum = 0.0
self.mean = 0.0
self.t = 0
self.n = 0
self.var = None
def calculate(self, y, w):
q = y - self.mean
tmp_sum = self.sum + w
r = q*w / tmp_sum
self.mean += r
self.t += q*r*self.sum
self.sum = tmp_sum
self.n += 1
if (self.sum == 0.0 or self.n < 2):
self.var = 0
else:
self.var = (self.t*self.n)/(self.sum*(self.n-1))
return (self.mean, self.var)
means = []
vars = []
st = StreamingStatistcs()
for y in Y:
m, v = st.calculate(y, 1.0)
means.append(m)
vars.append(np.sqrt(v))
fig, (ax1, ax2) = plt.subplots(1, 2)
fig.suptitle('Streaming statistics for $N=10^5$ observations')
ax1.plot(means)
ax1.hlines(y=10, xmin=0, xmax=N, colors="red")
ax1.set_title("Streaming mean")
ax2.plot(vars)
ax2.hlines(y=20, xmin=0, xmax=N, colors="red")
ax2.set_title("Streaming variance")
plt.show()
